समस्या: 3 किलोग्राम द्रव्यमान के एक ब्लॉक को 25 N के बाहरी बल द्वारा एक दीवार के खिलाफ लंबवत दबाया जाता है। ब्लॉक और दीवार के बीच घर्षण का गुणांक 0.5 है। ब्लॉक पर लगने वाले घर्षण बल का निर्धारण करें और यह भी निर्धारित करें कि ब्लॉक ऊपर की ओर जाएगा या नीचे की ओर।
Problem] A block of mass 3 kg is pressed vertically against a wall by an external force of 25 N. The coefficient of friction between the block and the wall is 0.5. Determine the frictional force acting on the block and whether the block will move upward or downward.Original Question set: friction numerical class 11 set 1 (in Hindi & English)
Solution:
To analyze the motion of the block pressed against the wall, we need to consider the forces acting on it. These forces include the normal force exerted by the wall, the force applied to the block, the force of gravity, and the frictional force. We will apply Newton’s second law to determine the direction of motion and the frictional force.
Given:
Mass of the block (m) = 3 kg
External force (F_external) = 25 N
Coefficient of friction (μ) = 0.5
Calculations:
Force of gravity (F_gravity) = m * g = 3 kg * 9.8 m/s² ≈ 29.4 N
Normal force (F_normal) = F_external= 25 N
Force of friction (F_friction) = μ * F_normal = 0.5 * 25 N ≈ 12.5 N
Since the force of friction (12.5 N upward) is less than the force of gravity (29.4 N downward), the block will move downward.
Also See for other such Numericals on friction: friction numerical class 11 set 1 (in Hindi & English)