In this post, we will derive the Average Velocity formula for equal distance intervals. In this specific case, a body travels equal distance intervals with different velocities, and we need to find out the average velocity and its formula.
Let’s see what this actually means and what is the formula.
Say, an object is moving from A to B (see Figure 1). The distance between A and B = AB = L meter
Say, this distance L is made of n number of equal distances each of length l meter.
So, we can write L = nl ………………………. (1)
Say the object passes these equal distances with different velocities like v1, v2, v3,…., and vn.
So total time required to cross the entire distance T = t1 + t2 + t3 +…. + tn = l/v1 + l/v2 + ….+ l/vn
=> T = l [1/v1 + 1/v2 + ….+ 1/vn ] ………………………. (2)
Average Velocity for equal distance intervals = L/T = nl / l [1/v1 + 1/v2 + ….+ 1/vn ]
Vavg = n/[1/v1 + 1/v2 + ….+ 1/vn ]
When n =2
then Vavg = 2/[1/v1 + 1/v2] =2v1 v2 /[v1 + v2]